Calculate the mass of iron in 10 kg of iron ore which contains 50% of the pure ferric oxide
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You can relate to this,
ferric oxide e.g Fe3O4 in 10kg iron ore Fe3O4 contain 10x 80/100 = 8kg now,1mole of Fe3O4 contain 3 mole of Fenow, no of mole of Fe3O4=8000g/(56 x 3+16 x 4) = 8000/232 =34.5
so, no of mole of Fe =3 x 34.5 =103.5 mole we know ,mole =weight/molecular weight 103.5 = weight/56 weight =103.5 x 56 g =5796 g =5.796 kg (approx )
You can relate to this,
ferric oxide e.g Fe3O4 in 10kg iron ore Fe3O4 contain 10x 80/100 = 8kg now,1mole of Fe3O4 contain 3 mole of Fenow, no of mole of Fe3O4=8000g/(56 x 3+16 x 4) = 8000/232 =34.5
so, no of mole of Fe =3 x 34.5 =103.5 mole we know ,mole =weight/molecular weight 103.5 = weight/56 weight =103.5 x 56 g =5796 g =5.796 kg (approx )
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