Question

calculate the mass of iron in 10kg of iron ore which contains 80%of pure ferric oxide

Answer 1

ferric oxide e.g Fe3O4
in 10kg iron ore Fe3O4 contain 10x 80/100 = 8kg
now,
1mole of Fe3O4 contain 3 mole of Fe
now,
no of mole of Fe3O4=8000g/(56 x 3+16 x 4) = 8000/232 =34.5

so, no of mole of Fe =3 x 34.5
=103.5 mole
we know ,
mole =weight/molecular weight
103.5 = weight/56
weight =103.5 x 56 g =5796 g =5.796 kg (approx )

Answer 2

Explanation:

5.796 kg approximately hope it helps mark as brainliest