Question

Calculate the mass of na2co3 required to prepare 250ml of 0.5N solution

Answer 1

hey !!!

Na = 23 u
c=12u
o=16u

now ,, atomic mass of na2co3
= 23×2+12+16×3
= 46+12+48
= 106u

Answer 2

Answer:

6.625 grams

Explanation:

molecular weight of Na2CO3 is 2(23)+12+3(16)=46+12+48=106

gram equivalent weight of Na2CO3 is 106/2=53

Given,Normality=0.5N

Volume of solution=250ml

we know that,

Normality (N)= wt/53×1000/250

0.5N=wt/53×4

wt=0.5×53/4

=6.625 grams

Hence,mass of Na2CO3 is 6.625 grams