Question

Calculate the mass of NaOH present in 0.11 M 250 cm3 aqueous solution

Answer 1

Answer:

1.1 g

Explanation:

M = 0.11M

V = 250 cm³ = 0.25 L

M = moles/volume

Let the given weight of NaOH = x  

Molecular weight of NaOH = 40 g

0.11 = (x/40)/0.25

0.11 x 40 x 0.25 = x

x = 1.1 g