Question

Calculate the mass of NH3 produced when 2g nitrogen react with 1g hydrogen. Which is the limiting reagent in this reaction.​

Answer 1

Explanation:

Answer

The balanced chemical equation is as follows:

N

2

+3H

2

→2NH

3

The molar masses of nitrogen, hydrogen and ammonia are 28 g/mol, 2 g/mol and 17 g/mol respectively.

28 g of nitrogen reacts with 6 g of hydrogen to form 34 g of ammonia.

2.00×10

3

g of nitrogen will react with

28

6

×2.00×10

3

=428.6 g hydrogen.

However, 1.00×10

3

g of dihydrogen are present.

Hence, nitrogen is the limiting reagent.

(i) Mass of ammonia produced =

28

34

×2×10

3

=2428.57 g

(ii) Hydrogen is the excess reagent. Hence, it will remain unreacted.

(iii) Mass of dihydrogen left unreacted =1.00×10

3

−428.6=571.4 g

Answer 2

Answer:

Dinitrogen and dihydrogen react with each other to produce ammonia according to the following chemical equation: N2 (g) + H2 (g) → 2NH3 (g) (i) Calculate .

Explanation:

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