Calculate the mass of one mole of electron of 55mg
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As we know that
1Kg=1061Kg=106mgMass of an electron = 9.1×10−319.1×10−31Kg
=9.1×10−25mg.9.1×10−25mg.
Next,number of electrons(X) present in 0.55 mg :
0.55/(9.1×10−25)=0.604×10240.55/(9.1×10−25)=0.604×1024
Further ;
no of moles (n) = X/NX/N
N is Avogadro's constant .
=n=0.604×1024/(6.023×1023)=1.0034793.=n=0.604×1024/(6.023×1023)=1.0034793.
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1Kg=1061Kg=106mgMass of an electron = 9.1×10−319.1×10−31Kg
=9.1×10−25mg.9.1×10−25mg.
Next,number of electrons(X) present in 0.55 mg :
0.55/(9.1×10−25)=0.604×10240.55/(9.1×10−25)=0.604×1024
Further ;
no of moles (n) = X/NX/N
N is Avogadro's constant .
=n=0.604×1024/(6.023×1023)=1.0034793.=n=0.604×1024/(6.023×1023)=1.0034793.
Hope it's help you
Please mark me in brain list answer
Shahnawaz786786:
Please mark me in brain list answer
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