calculate the mass of oxalic acid required to prepare 1000 ml ( N/20) solution
Answers
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Answer:
1.45 gms of oxalic acid is needed
Explanation:
according to the question given normality is 1/20 so we need 1 litre of this solution. so when we multiply the volume with normality we get the no of equivalents
the no of equivalents is given by the unknown mass divided by the equivalent mass
now to calculate the equivalent mass divide the molar mass of oxalic acid which is 58 by its n factor which is 2 so when you substitute all the given data it comes out as 1.45 gms
N/ 20 ×1000ml= no of equivalents=1/20
no of equivalents = Μ/equivalent mass
equivalent mass = 58/2
so 1/20= M /29
SO MASS M IS 1.45