Calculate the mass of oxygen required to burn 14g methane completely
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bhai question correct kar phala
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question is alright. no error there.
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CH4(g) + 2(O2(g)) → CO2 + 2(H2O)
Thus, 1mol Methane requires 2 mol Oxygen Gas.
Hence, 16g CH4 requires 64g O2
》14g CH4 requires (64×(14/16))g O2
= 56g O2.
Thus, 1mol Methane requires 2 mol Oxygen Gas.
Hence, 16g CH4 requires 64g O2
》14g CH4 requires (64×(14/16))g O2
= 56g O2.
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