Calculate the mass of potassium nitrate obtained by neutralizing a solution containing 28 g of potassium hydroxide with nitric acid (Atomic mass of nitrogen = 14; potassium = 39; oxygen = 16 and hydrogen = 1)?
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Answer:
50.5g
Explanation:
KOH+HNO3----->KNO3+H2O
weight of KOH=39+16+1=56g
Weight of KNO3=39+14+3*(16)=101g
56g of KOH gives 101g of KNO3
So, 28g gives 50.5g of KNO3
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