Question

Calculate the mass of sodium acetate (CH 3 COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol –1

Answer 1

∴ Mass of the compound = 15.37 g.

Answer 2

Answer:

0.375M solution means 0.375 moles in 1 L of solution.

1000mL of solution contains 0.375 moles

1mL of solution⟶10000.375moles

500mL of solution⟶10000.375×500

                              

                                        ⟶0.1875

No. of moles=Molar MassMass

0.1875mol=82.0245 gmol−1Mass

∴ Mass of the compound = 15.37 g.

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