Question

Find
quadratic polynomial each
with the given numbers as the sum
and product of its zeroes,
respectively​

Answer 1

Answer:

sun of zeros = à+ß

product of zeros à ß

Thank you

Answer 2

Answer:

(i)1/4, -1 Now formula of quadratic equation is x²-(Sum of root)x + (Product of root) = 0 Plug the value in formula we get x² –(1/4)x -1 = 0 Multiply by 4 to remove denominator we get 4x² - x -4 = 0

(ii) √2 , 1/3 Now formula of quadratic equation is x²-(Sum of root)x + (Product of root) = 0 Plug the value in formula we get x² –(√2)x + 1/3 = 0 Multiply by 3 to remove denominator we get 3x² - 3√2 x + 1 = 0 (iii) 0, √5 Now formula of quadratic equation is x²-(Sum of root)x + (Product of root) = 0 Plug the value in formula we get x² –(0)x + √5 = 0 simplify it we get x² + √5 = 0 (iv) 1,1 Now formula of quadratic equation is x²-(Sum of root)x + (Product of root) = 0 Plug the value in formula we get x² –(1)x + 1 = 0 simplify it we get x² - x + 1 = 0 (v) -1/4 ,1/4 Now formula of quadratic equation is x²-(Sum of root)x + (Product of root) = 0 Plug the value in formula we get x² –(-1/4)x + 1/4 = 0 multiply by 4 we get 4x² + x + 1 = 0 (vi) 4,1 Now formula of quadratic equation is x²-(Sum of root)x + (Product of root) = 0 Plug the value in formula we get x² –(4)x + 1 = 0 x2 –4x + 1 = 0