calculate the mass of sodium acetate (CH3COONa) required to make 500ml of o. 375ml molar aqueous solution . Molar mass of sodium acetate is 82.0245g/mol.
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Answer:
0.015g
Explanation:
from the formula of molarity
0.375/1000L=x*1000/500 ..........(1)
x= no.of moles of CH3COONa
LHS term= molarity divided by 1000 to convert in litres
RHS term denominator = 500(volume of solution in litres) which is when divided by 1000 to convert in litres and simple maths se 1000 numerator me chala gaya aur x se multiply hua
FROM eq^1
x=0.00019moles
now no.of moles= given mass/molar mass
0.00019=given mass/82.0245
given mass=0.015g
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