Question

calculate the mass of sodium acetate (ch3coona) required to make 500 ml of 0.375 molar aqueous solution. molar mass of sodium acetate is 82.0245 g/mol​

Answer 1

Answer:

0.375 M solution of CH3COONa = 0.375 moles of CH3COONa/1000ml

No. of moles of CH3COONa in 500ml =

1000

0.375×500=0.1875 moles

Molar mass of sodium acetate = 82.0245 g/mole

∴ mass of CH3COONa required =82.0245×0.1875=15.38g