Question

calculate the mass of sodium acetate (CH3COONa) required to make 500 ml of 0.375 molar aqueous solution. molar mass of sodium acetate is 82.0245 g/mol​

Answer 1

Given :

➨ Volume of solution = 500 ml

➨ Molarity of solution = 0.375 M

➨ Molar mass of sodium acetate = 82.0245 g/mol

To Find :

➠ Mass of sodium required to make this solution.

Molarity :

➛ Symbol : M

➛ Definition : Number of moles of solute dissolved one litre (or one dm³) of solution.

➛ Effect of temperature : No effect

➛ Formula :

$\bigstar\:\underline{\boxed{\bf{\purple{M=\dfrac{W\times 1000}{M_w\times V}}}}}$

where,

◕ W denotes weight of solute

◕ Mw denotes molar mass of solute

◕ V denotes volume of solution (in ml)

Calculation :

$\Rightarrow\sf\:M=\dfrac{W\times 1000}{M_w\times V}\\ \\ \Rightarrow\sf\:0.375=\dfrac{M\times 1000}{82.0245\times 500}\\ \\ \Rightarrow\sf\:W=\dfrac{0.375\times 82.0245}{2}\\ \\ \Rightarrow\underline{\boxed{\bf{\orange{W=15.37\:g}}}}\:\gray{\bigstar}$

Answer 2

$\bigstar$ $\sf{\blue{\underline{\underline{\green{To\:Find:-}}}}}$

• The mass of Sodium Acetate $\tt{(CH_3COONa)}$ .

$\bigstar$ $\sf{\green{\underline{\underline{\blue{SOLUTION:-}}}}}$

☞ GIVEN :-

• Molar Concentration of aq. solution = 0.375M

• Volume of aq. solution = 500 ml

• Molar mass of Sodium Acetate = 82.0245 g/mol

☞ FORMULA :-

$\checkmark\:\tt{\underline{\purple{\boxed{Mole\:=\:{\dfrac{given\:mass}{molar\:mass}}\:}}}}$

☞ CALCULATION :-

(✷✷) “0.375 M” aqueous solution means that “1000ml of the solution contains 0.375 mole Sodium Acetate” .

➜ So, 500ml of the solution should contain sodium acetate is ,

$\tt{\:\:\:\:\:\:=\:{\dfrac{0.375}{2}}\:mole}$

☞ Now, Mass of Sodium Acetate required ,

$\tt\underline{\blue{\boxed{mass\:of\:(CH_3COONa)\:=\:[moles\:of\:(CH_3COONa)]\:\times\:[Molar\:mass\:of\:(CH_3COONa)]\:}}}$

$\tt{\implies\:Mass\:of\:(CH_3COONa)\:=\:{\dfrac{0.375}{2}}\:\times\:82.0245}$

$\tt{\implies\:Mass\:of\:(CH_3COONa)\:=\:15.38\:gram}$

$\bigstar\:\underline{\boxed{\bf{\red{Required\:Answer\::\:Mass\:of\:(CH_3COONa)\:required\:=\:15.38\:g\:}}}}$