what is resultant capacitance
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(1) Resultant capacitance will be 4 mF
(step1) = 2 mF , 4 mF and 3 mF , 5 mF are in series so they will added as R1 + R2
(step2) = Now 6mF and 8 mF are in parallel so net capacitance will be 1/R1 + 1/R2
On calculating we will get 4 mF capacitance
(2) Charge = capacitance × voltage
q = 0.8 c
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