Question

Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of
0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol-.​

Answer 1

Answer:

0.375 M solution of CH3COONa = 0.375 moles of CH3COONa/1000ml

No. of moles of CH3COONa in 500ml =10000.375×500=0.1875 moles

Molar mass of sodium acetate = 82.0245 g/mole

∴ mass of CH3COONa required =82.0245×0.1875=15.38g

Hope it helps you.

Mark as brainleist.

Answer 2

please mark me as brainlist And follow me