Question

Calculate the mass of sodium acetate (CH₃COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol⁻¹

Answer 1

$\huge{hiii dear ^-^}$

. ✨Answer:-✨

0.375 M aqueous solution of sodium acetate means that 1000 mL of solution containing 0.375 moles of sodium acetate.

∴No. of moles of sodium acetate in 500 mL = (0.375/1000)×500 = 0.375/2 = 0.1875

Molar mass of sodium acetate = 82.0245g mol-1

∴Mass of sodium acetate acquired =  0.1875×82.0245 g = 15.380g



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hope its help uh...


$Sumit Tiwari from Azamgarh (up)$