ram saves Rs.320 during the first year. Rs.360 in the second year and Rs.400 in the third year. if he continues his saving in the sequence, in how many years will he saves Rs 20000?
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Heya!!
refer to given attachment please
refer to given attachment please
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vikas324:
answer 25 hai
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Sum is given as 20000
The given pattern is in A.P
A.p stands for arithmetic progression
a = 320
d=40
S = n /2 [ 2a + ( n -1) d ]
20000= n/2 [ 640 + 40n-40]
20000=n /2×40 [16+n-1]
20000 × 2 ÷ 40 = 16n + n ^2 -n
1000= n^2 +15n
n^2 +15n -1000=0
n^2 + 40n-25n -1000=0
n (n+ 40) - 25 (n+40)=0
(n+40)(n-25) = 0
n= 25 years
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The given pattern is in A.P
A.p stands for arithmetic progression
a = 320
d=40
S = n /2 [ 2a + ( n -1) d ]
20000= n/2 [ 640 + 40n-40]
20000=n /2×40 [16+n-1]
20000 × 2 ÷ 40 = 16n + n ^2 -n
1000= n^2 +15n
n^2 +15n -1000=0
n^2 + 40n-25n -1000=0
n (n+ 40) - 25 (n+40)=0
(n+40)(n-25) = 0
n= 25 years
Thank u ★ ★ ★
#ckc
Hope it helps
Plz mark brainliest
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