Question

calculate the mass of sodium carbohydrate which has same number of atoms as a present in 12.3 gram of magnesium sulphate​

Answer 1

Explanation:

Molecular mass of MgSO4.7H2O is 24+32+64+7(18)=246 gram.

No of moles= 12.3/246=0.05moles.

As per the question moles of Na2CO3 is 0.05 moles.

Molecular mass of Na2CO3 is 46+12+48=106gram.

0.05 moles will have mass =0.05×106=5.3grams.

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