The ages of two friends A and B differ by 3 years. A’s father D is twice as old as A and B is twice as old as his sister C. The ages of D and C differ by 40 years, find the age of his sister C.
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We know that A-B=3y
D=2(A+B)=2C
D-C=40.....
D=2C.
2C-C=40 (substituting D=2C)
C=40.
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