Question

calculate the mass of sodium ions in 1.24g of sodium sulphate​

Answer 1

Answer:

4Na+O2→2Na2O.

By the stoichiometry of this reaction if 5 mol natrium react, then 2.5 mol Na2O should result.

Explanation:

The molecular mass of natrium oxide is 61.98 g⋅mol−1. If 5 mol natrium react, then 52 mol×61.98 g⋅mol−1 = 154.95 g natrium oxide should result.

So what have I done here? First, I had a balanced chemical equation (this is the important step; is it balanced?). Then I used the stoichiometry to get the molar quantity of product, and converted this molar quantity to mass. If this is not clear, I am willing to have another go.