Calculate the mass of sodium sulphate required to prepare it's 20percent solution in 100gram of water.
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Mass percent = Mass of solute / Mass of solution × 100
%(m/m) = [m / (m + M)] × 100
20 = [m / (m + 100)] × 100
0.2 = m / (m + 100)
0.2m + 20 = m
0.8m = 20
m = 25 grams
Mass of sodium sulphate = 25 grams
%(m/m) = [m / (m + M)] × 100
20 = [m / (m + 100)] × 100
0.2 = m / (m + 100)
0.2m + 20 = m
0.8m = 20
m = 25 grams
Mass of sodium sulphate = 25 grams
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Answer:
Given that the mass percent of sodium sulphate solution is 20%. Let the mass of sodium sulphate which is required to prepare this solution be x grams. Given that the mass of water is 100 g. Thus, 25g of sodium sulphate is required.
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