Chemistry, asked by sourishmirbahar, 6 months ago

calculate the mass of sodium sulphate required to prepare it's 10 percent (mass by mass percent) solution in 45gm of water​

Answers

Answered by Anonymous
2

Answer:

Given that the mass percent of sodium sulphate solution is 20%. Let the mass of sodium sulphate which is required to prepare this solution be x grams. Given that the mass of water is 100 g. Thus, 25g of sodium sulphate is required.

Answered by Twena
0

Answer:

25 grams of sodium sulphate is required..

Explanation:

MASS OF SOLUTION =MASS OF SOLUTE + MASS OF SOLVENT

GIVEN THAT THE MASS PERCENT OF SODIUM SULPHATE IS 20%..

LET THE MASS OF SODIUM SULPHATE WHICH IS REQUIRED TO PREPARE THIS SOLUTION BE "X" GRAMS.

GIVEN THAT THE MASS OF WATER IS 100 GRAMS

SO,

20={X/(X+100)}*100

20/100={X/X+100}

1/5=X/X+100

X+100/5=X

X+100=5X

5X-X=100

4X=100

X=100/4

X=25....

HOPE U GOT IT CLEARLY

THANK U ...

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