Chemistry, asked by phalak850, 1 year ago

Calculate the mass of sodium sulphate required to prepared if 20%solution in 100g of water

Answers

Answered by asif2996
37
Let the mass of sodium sulphate required be = x g 

The mass of solution would be = (x +100) g 

x g of solute in (x + 100) g of solution 

20% = x/x+100 x100 

20 x + 2000= 100 x 

80 x = 2000 

x = 2000/ 80 

= 25 g
25g of sodium sulphate required
Answered by sudhir6446
6

Answer:

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Explanation:

Mass of the solution = mass of solute + mass of solvent

Given that the mass percent of sodium sulphate solution is 20%.

Let the mass of sodium sulphate which is required to prepare this solution be x grams.

Given that the mass of water is 100 g.

So,

20 = [x/(x + 100)] * 100

20/100 = [x/x + 100]

1/5 = x/x + 100

x + 100/5 = x

x + 100 = 5 x

5 x - x = 100

4 x = 100

x = 100/4

x = 25

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