Calculate the mass of sodium sulphate required to prepared if 20%solution in 100g of water
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Answered by
37
Let the mass of sodium sulphate required be = x g
The mass of solution would be = (x +100) g
x g of solute in (x + 100) g of solution
20% = x/x+100 x100
20 x + 2000= 100 x
80 x = 2000
x = 2000/ 80
= 25 g
25g of sodium sulphate required
The mass of solution would be = (x +100) g
x g of solute in (x + 100) g of solution
20% = x/x+100 x100
20 x + 2000= 100 x
80 x = 2000
x = 2000/ 80
= 25 g
25g of sodium sulphate required
Answered by
6
Answer:
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Explanation:
Mass of the solution = mass of solute + mass of solvent
Given that the mass percent of sodium sulphate solution is 20%.
Let the mass of sodium sulphate which is required to prepare this solution be x grams.
Given that the mass of water is 100 g.
So,
20 = [x/(x + 100)] * 100
20/100 = [x/x + 100]
1/5 = x/x + 100
x + 100/5 = x
x + 100 = 5 x
5 x - x = 100
4 x = 100
x = 100/4
x = 25
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