Why is k4 [fe(cn)6] diamagnetic and [fe(h2o)6]cl2 paramangnetic? And how to calculate it
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when we find electronic configuration of K4[Fe(CN)6] then there is no unpaired electrons.and we know that when there is all paired electrons then the complex is diamagnetic.
and when we find the electronic configuration of [Fe(H2O)6]Cl2 then there is 4 unpaired electrons.so this complex is pera magnetic.
in 1st complex CN is a strong ligand so the electrons that present in 3d orbital will paired.
and in 2nd complex H2O is a weak ligand so the electrons will not be paired.
I explain the 1st complex that how we calculate this.
thanks ☺
when we find electronic configuration of K4[Fe(CN)6] then there is no unpaired electrons.and we know that when there is all paired electrons then the complex is diamagnetic.
and when we find the electronic configuration of [Fe(H2O)6]Cl2 then there is 4 unpaired electrons.so this complex is pera magnetic.
in 1st complex CN is a strong ligand so the electrons that present in 3d orbital will paired.
and in 2nd complex H2O is a weak ligand so the electrons will not be paired.
I explain the 1st complex that how we calculate this.
thanks ☺
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