Question

calculate the mass of sulfur dioxide produced by burning 16 g of sulfur in excess of oxygen in contact process ( average atomic mass : s=32 u o= 16 u​

Answer 1

Answer:

The mass of sulfer dioxide is 48 unit

Explanation:

S+ O2= SO2

1 mole of sulfur and 1 mole of oxygen reacts and make one mole of sulfur dioxide.

As given,  atomic mass : s=32 unit  o= 16 unit

therefore the atomic mass of so2= 32+(16*2)

                                                        = 64 unit

now if we say that we will use 16g of sulfer

then the atomic mass of so2= 16+(16*2)

                                                        = 48 unit

Answer 2

32 g of sulfur dioxide produced by burning 16 g of sulfur in excess of oxygen in contact process.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{16g}{32g/mol}=0.5moles$

$S+O_2\rightarrow SO_2$

As oxygen is in excess, sulphur is the limiting reagent as it limits the formation of product.

1 mole of sulphur (S) produce = 1 mole of sulphur dioxide $(SO_2)$

0.5 mole of sulphur (S) produce= $\frac{1}{1}\times 0.5=0.5$ mole of sulphur dioxide $(SO_2)$

Mass of sulphur dioxide=$moles\times {\text{ Molar mass}}=0.5mol\times 64g/mol=32g$

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