calculate the mass of sulphur dioxide gas which will contain same number of molecule as present in 4.4g of carbon dioxide
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Hey chika ❤
Here's ur answer-
we know that,
![moles \: = \: given \: mass \: \div \: molar \: mass \: moles \: = \: given \: mass \: \div \: molar \: mass \:](https://tex.z-dn.net/?f=moles+%5C%3A++%3D++%5C%3A+given+%5C%3A+mass+%5C%3A++%5Cdiv++%5C%3A+molar+%5C%3A+mass+%5C%3A+)
Given,
Mass of carbon = 4.4
and, molar mass of carbon = 44
So,
![moles \: = \: 4.4 \div 44 moles \: = \: 4.4 \div 44](https://tex.z-dn.net/?f=moles+%5C%3A++%3D++%5C%3A+4.4+%5Cdiv+44)
![moles \: = \: 0.1 moles \: = \: 0.1](https://tex.z-dn.net/?f=moles+%5C%3A++%3D++%5C%3A+0.1)
Hence,
we have to calculate the mass of 0.1 mole os sulphur dioxide [SO2]
Again,
![moles \: = \: given \: mass \: \div \: molar \: mass moles \: = \: given \: mass \: \div \: molar \: mass](https://tex.z-dn.net/?f=moles+%5C%3A++%3D++%5C%3A+given+%5C%3A+mass+%5C%3A++%5Cdiv++%5C%3A+molar+%5C%3A+mass+)
Moles = 0.1
and, molar mass = 64
![= > 0.1 \: = \: mass \: \div 64 = > 0.1 \: = \: mass \: \div 64](https://tex.z-dn.net/?f=+%3D+%26gt%3B++0.1+%5C%3A++%3D++%5C%3A+mass+%5C%3A++%5Cdiv+64)
From above , we can say that
![mass \: of \: moles \: =no.of \: moles \: \times molar \: mass mass \: of \: moles \: =no.of \: moles \: \times molar \: mass](https://tex.z-dn.net/?f=+mass+%5C%3A+of+%5C%3A+moles+%5C%3A+%3Dno.of+%5C%3A++moles+%5C%3A++%5Ctimes+molar+%5C%3A+mass)
![mass \: of \: moles \: = 0.1 \times 64 mass \: of \: moles \: = 0.1 \times 64](https://tex.z-dn.net/?f=mass+%5C%3A+of+%5C%3A+moles+%5C%3A++%3D+0.1+%5Ctimes+64)
![mass \: = \: 6.4 mass \: = \: 6.4](https://tex.z-dn.net/?f=mass+%5C%3A++%3D++%5C%3A+6.4)
Hope it helps ✔
Here's ur answer-
we know that,
Given,
Mass of carbon = 4.4
and, molar mass of carbon = 44
So,
Hence,
we have to calculate the mass of 0.1 mole os sulphur dioxide [SO2]
Again,
Moles = 0.1
and, molar mass = 64
From above , we can say that
Hope it helps ✔
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