Question

Calculate the mass of water which contains the same number of molecules as are contained in 60g of oxygen

Answer 1

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Answer 2

The mass of water which contains the same number of molecules as are contained in 60g of oxygen is 33.77 g

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

given mass of oxygen=  60 g

Molar mass of oxygen $(O_2))$ = 32 g/mol

Putting in the values we get:

$\text{Number of moles}=\frac{60g}{32g/mol}=1.875moles$

1 mole of oxygen $O_2$ contains=$6.022\times 10^{23}$ molecules

Thus 1.875 moles of oxygen $O_2$ contain=$\frac{6.022\times 10^{23}}{1}\times 1.875=11.30\times 10^{23}$ molecules

$6.022\times 10^{23}$ molecules of water are contained in 18 g of water $(H_2O)$

Thus $11.30\times 10^{23}$ molecules of water are contained in=$\frac{18}{6.022\times 10^{23}}\times 11.30\times 10^{23}=33.77g$ of water $(H_2O)$

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Mole Concept

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Avogadros law

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