Question

Calculate the mass percentage of benzene and carbon tetrachloride is 22 g of benzene is dissolved in 122 g of carbon tetrachloride

Answer 1

Mass of the total mixture= 22g(benzene) + 122g(CCL4)=144g

Mass % of benzene=(Mass of benzene/Mass of the total mixture)*100
=(22g/144g)*100
=15.28%
Similarly, Mass % of CCL4=(Mass of CCL4/Mass of the total mixture)*100
=(122g/144g)*100
=84.72%

In general, Mass% of any component(X) in a mixture
=(Mass of component(X)/mass of total mixture)*100
@skb

Answer 2

Given,

Benzene (C6H6) is 22g in the solution.

Carbon tetrachloride (CCl4) is 122g in solution

We know,

Mass Percentage of solute =

Total mass of the solution = 22g (benzene) + 122g (carbon tetrachloride)

= 144g

Mass percentage of benzene (C6H6) = 15.28%

Note: The second method to calculate the Mass percentage of carbon tetrachloride = 100 – Mass % of C6H6

= 100 - 15.28%

= 84.72%