Question

Calculate the mass percentage of benzene(C6H6) and carbon tetrachloride(CCl4) if 22g benzene is dissolved in 122g of carbon tetrachloride. ​

Answer 1

Given :

• mass of benzene ( m 1 )= 22 g

• mass of carbon tetrachloride ( m 2 )= 122 g /

Solution:

$\boxed{\%m/ m = \frac{mass \: of \: solute}{mass \: of \: solution} \times 100}$

mass of solution

= mass of solute + mass of solvent

= 22 + 122

= 144 g

mass of solution = 144 g

$\%m/ m = \frac{m \: 1}{m \: 1 + m2} \times 100$

$\%m/ m = \frac{22}{144} \times 100$

$\boxed{\%m/ m =15.3\%}$