Question

calculate the mass percentage of nitrogen in NH4NO3.(N=14; H=1; O=16)​

Answer 1

Answer:

Percent composition of N is 28g80g×100%=35% .

Answer 2

Answer:

For Compound NH4NO3 ,

Molecular Mass

= 14 + ( 4 ×1 ) + 14 + ( 16 × 3 )

= 14 + 4 + 14 + 48

= 80

Therefore , A / Q : -

Mass % of Nitrogen

= ( Mass of Nitrogen atoms / Mass of molecule ) × 100

( Since , 2 Nitrogen atoms are present in Given molecule

So , Mass of Nitrogen atoms = 2 × 14 = 28 )

= ( 28 / 80 ) × 100

= 35 %