Question

calculate the mass percentage of sodium, carbon and oxygen in sodium bicarbonate NaHCO3​

Answer 1

Mass of elements:-

Na=23

H=1

C=12

O=16

Molecular mass=23+1+12+3(16)

= 23+1+12+48

= 24+12+48

= 84

Percentage composition=

$= \frac{Mass \: \: of \: \: sodium}{Mass \: \: of \: \: NaHCO3} \times 100$

$= \frac{23}{84} \times 100$

$= \frac{ 23 \times 25}{21}$

=27.380%

=27.38% (approx)