Question

Calculate the maximum height attained by the body thrown vertically upward with a velocity of 9.8 m/s

Answer 1

v=u+at
0=9.8+(-9.8t)
9.8t=9.8
t=9.8/9.8
t=1s
s=ut+1/2at^2
=9.8*1+1/2*(-9.8)*1^2
=9.8+1/2*9.8
=9.8+4.9
=14.7m