Calculate the mean deviation about mean of set of first n natural number when n is odd natural number
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given:
set of n natural numbers ending with n which is odd number.
to find :
mean deviation of given set of numbers.
solution:
Mean of first n natural numbers where n is an even number is
=1/2[n/2+(n+1)/2]
=1/2[n/2+(n+1)/2]
=(2 n+1)/4
mean deviation =∑|xi−x n|/n =1/4n
[1+3+5+9+.......+ nth odd number]
now sum of odd numbers =n^2
=(1/4 n)n^2
=n/4
set of n natural numbers ending with n which is odd number.
to find :
mean deviation of given set of numbers.
solution:
Mean of first n natural numbers where n is an even number is
=1/2[n/2+(n+1)/2]
=1/2[n/2+(n+1)/2]
=(2 n+1)/4
mean deviation =∑|xi−x n|/n =1/4n
[1+3+5+9+.......+ nth odd number]
now sum of odd numbers =n^2
=(1/4 n)n^2
=n/4
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