Question

Calculate the mean deviation about the mean of the digits
1,2,3,4,5,6,7,8,9.
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Answer 1

Step-by-step explanation:

Mean of the digits 1,2,3,4,5,6,7,8,9 =>

(1+2+3+4+5+6+7+8+9)/9 =>45/9 =>5.

Mean deviation =>[(1-5)+(2-5)+(3-5)+(4-5)+(5-5)+(6-5)+(7-5)+(8-5)+(9-5)]/9 =>(-4-3-2-1+0+1+2+3+4)/9=>0. Hope it helps you.

Answer 2

Given:

Digits: 1,2,3,4,5,6,7,8,9

To find:

The mean deviation about the mean of the digits

Solution:

We can find the mean deviation by following the steps given below-

We know that to find the mean deviation, we first need to find the mean of digits.

The mean of digits=Sum of digits/ Number of digits

Sum of all digits=1+2+3+4+5+6+7+8+9

=45

Mean=45/9

=5

Mean deviation=

$sum \: of |xi - m| \div number \: of \: terms$

where xi refers to the digits, m is the mean.

Calculating the mod of difference in digits and mean,

$|1 - 5| = | - 4| = 4$

$|2 - 5| = | - 3| = 3$

$|3 - 5| = | - 2| = 2$

$|4 - 5| = | - 1| = 1$

5-5=0

6-5=1

7-5=2

8-5=3

9-5=4

On adding the differences, we get

4+3+2+1+0+1+2+3+4=20

Mean deviation=20/9

=2.22

Therefore, the mean deviation from the mean of the digits is 2.22.