Question

Calculate the minimum and maximum capacitance obtained by combining 3 capacitors of capacitances 0.5mf, 0.3mf and 0.2mf

Answer 1

Answer:

min:  3/31 mf

max: 1 mf

Explanation:

maximum: 1/(1/0.5+1/0.3+1/0.2)= 1/((60+100+150)/30)=30/310=3/31 mf (all series)

minimum: 0.5+0.3+0.2=1mf all capacitors are parallel