If A (-5,7), B (-4,-5), C (-1,-6) and D (4,5) are the vertices of a quadrilateral, find the are of the quadrilateral ABCD.
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Hello here is your answer by Sujeet yaduvanshi ☝☝☝☝☝☝☝☝☝
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Solution:
Area of triangle ABC= 1/2[(-5)(-5+6) + (-4)(-6-7) +(-1)(7+5) ]
= 1/2 ( -5 +52 -12)
= 35/2
Also,
area of triangle ACD = 1/2[(-5)(-6-5)+ (-1)(5-7)+(4)(7+6)]
= 1/2 (55+ 2 + 52)
=109/2
Therefore,
Area of quad. ABCD = area of triangle ABC + area of triangle ACD = 35/2 + 109/2 = 144/2 = 72 sq.unit
___________________________
Answer:-. 72 sq.unit
that's all
Thanks for following!!!!!
Solution:
Area of triangle ABC= 1/2[(-5)(-5+6) + (-4)(-6-7) +(-1)(7+5) ]
= 1/2 ( -5 +52 -12)
= 35/2
Also,
area of triangle ACD = 1/2[(-5)(-6-5)+ (-1)(5-7)+(4)(7+6)]
= 1/2 (55+ 2 + 52)
=109/2
Therefore,
Area of quad. ABCD = area of triangle ABC + area of triangle ACD = 35/2 + 109/2 = 144/2 = 72 sq.unit
___________________________
Answer:-. 72 sq.unit
that's all
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