Math, asked by Anchalrajput6, 1 year ago

If A (-5,7), B (-4,-5), C (-1,-6) and D (4,5) are the vertices of a quadrilateral, find the are of the quadrilateral ABCD.

Answers

Answered by Anonymous
3
Hello here is your answer by Sujeet yaduvanshi ☝☝☝☝☝☝☝☝☝


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Solution:
Area of triangle ABC=  1/2[(-5)(-5+6) + (-4)(-6-7) +(-1)(7+5) ]

= 1/2 ( -5 +52 -12)

= 35/2


Also,

area of triangle ACD = 1/2[(-5)(-6-5)+ (-1)(5-7)+(4)(7+6)]

= 1/2 (55+ 2 + 52)

=109/2

Therefore,

Area of quad. ABCD = area of triangle ABC​ + area of triangle ACD = 35/2 + 109/2 = 144/2 = 72 sq.unit


___________________________

Answer:-. 72 sq.unit




that's all

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