Question

Calculate the molality and molarity of a 15% solution (W/V) of H2SO4 , if density of solution is 1.02 gm/ml .

Answer 1

Hey there!


Refer to the following attachment...


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Answer 2

Hey!!

Here is your answer -

15% H₂SO₄ solution means 15 g of H₂SO₄ is present in 100 g of Water.

No. of moles of H₂SO₄ = 15 g / 98 g/mol = 0.153 mol

Weight of solvent = 100g - 15g = 85g = 85 × 10^-3 kg

Molality = Moles of solute / Weight of Solvent in kg

= 0.153 / (85 × 10^-3)

= 1.8 m

Molality of given solution is 1.8 m ……[1]

Volume of solution = Mass of solution / Density

= 100 g / 1.1 g/cm^3

= 90.90 cm^3

= 0.090 Litres

Molarity = Moles of solute / Volume of solution in litres

= 0.153 / 0.090

≈ 1.7 M

Molarity of given solution is 1.7 M ……[2]