Question

Calculate the molality of 1 litre solution of 93%h2so4 solution. Density of the solution is 1.84 gm|ml

Answer 1

Answer:

532.9 m

Explanation:

VOL - 1 L

Mass - 1840 g

H2SO4 = 93/100 * 1840

            = 1711.2

moles = 1711.2/36.5

46.9 moles

solvent = 1800 - 1711.2

88.8g

molality = 46.9/88.8/1000 = 532.9 m