Question

Calculate the molality of 9.8% (w/w) solution of sulphuric acid. Given the density of solution is 1.02g/ml

Answer 1

9.8%w/w means 9.8gr in 100gr of solution

the mass of solvent is 100-9.8=90.2 gr

molality=mass of solute/molar mass of solute*1000/mass of solvent

=9.8/98*1000/90.2

=1.108molality (m)

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