Question

calculate the molality of a 0.5m h2so4 solution having density d g/ ml.​

Answer 1

Answer: molality = no of moles of solute / mass of solvent per kg

Hence let mass of solvent be I kg =1000g

then no of moles of solute is 1

Molar mass of h2so4= 98g

Mass of solute= no of moles of solute * molar mass

Mass of solute = 98g

Total mass of solution = 98+1000=1098g

Volume of solution= mass /density

=1098/d

Molarity = no of moles of solute / volume of solution in l

M= 98/1098*d

=0.08d

Explanation:

Answer 2

Mass or molecular mass of H2SO4 =98g

.

. . Molality =n/M, where n is the number of moles and M is the mass.

= 0.5

98. =0.0051