Question

Calculate the molality of a solution containing 15g of methanol (CH3OH) in 150 g of solvent

Answer 1

Answer:

Molality = 3.133 m

Explanation:

moles of methanol = given mass / molecular mass = 15 / 32 = 0.47

mass of solvent = 150/1000 kg = 0.15

Molality = moles of solute / mass of solvent in kg

Molality = 0.47 / 0.15

Molality = 3.133 m