Question

Calculate the molality of an aqueous solution containing 3.0g of
urea (mol.mass=60) in 250g of water.

Answer 1

no. of moles of urea=given mass\molar =3\60=0.05mol
molality=no. of mole\mass of solvent(in kg)
             =0.05*1000\250=0.2m

Answer 2

Answer:

0.2m

Explanation:

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