Chemistry, asked by biopriy, 1 year ago

calculate the molality of solution 93% of h2so4 w/v% density is 1.84 gm/ml

Answers

Answered by dattahari09

9

Answer:10.42m

Explanation:

93% 93 GM in 100 ml of solution

Weight of solution, 100x1.84=184 gm

Weight of solvent =184-93=91

m =moles /W

Moles =93/98=0.94

m = 0.94/91 x1000 =10.42 mole/kg

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