Question

Calculate the molality of solution containing 3g glucose dissolved in 30g of water.

Answer 1

Gonna use an image here.

Answer 2

Answer: 0.55m

Explanation:

Molality is the number of moles of solute dissolved per kg of solvent.

$Molality=\frac{\text{given mass of compound}}{\text{molar mass of compound}\times \text{weight of solvent in kg}}$

given mass of glucose = 3g

molar mass of glucose = 180 g/mol

weight of water = 30 g= 0.03 kg

$Molality=\frac{3}{180g/mol\times 0.03kg}=0.55m$