Calculate the molar conductivity at infinite dilution of AgCl from the following data:
A°(AgNO3) = 13.34mSm-mol-1, 4°(KCI) = 14.99mSm-mol-4,1°(KNO3) = 13.34mSmềmol-1
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Given:
A°(AgNO3) = 13.34mSm-mol-1,
A°(KCI) = 14.99mSm-mol-1,
A°(KNO3) = 13.34mSmềmol-1
To find:
Molar conductivity at infinite dilution of AgCl.
Solution:
The reaction will be:
KCl + AgNO3 → KNO3 +AgCl
As we know that:
molar conductivity of reactant = molar conductivity of product
14.99 + 13.34 = 13.34 + molar conductivity of AgCl
molar conductivity of AgCl = 14.49 mSm-mol-1
Therefore the molar conductivity at infinite dilution of AgCl is 14.49 mAm-mol-1.
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