calculate the molar volume of 2.8g nitrogen at STP
Answers
Answered by
1
Answer:
28g = 22.4l
2.8g = 2.24l
Answered by
2
Answer:
NO OF MOLES =GIVEN WEIGHT/MOLAR WEIGHT
NO. OF MOLES=2.8/28
NO. OF MOLES=0.1
1 MOLES OF ANY GAS OCCUPIES 22.4 L
SO,0.1 MOLES WILL OCCUIPY
22.4*0.1 L
2.24 L IS YOUR ANSWER
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