Question

Calculate the molarity and molality of 93% H2SO4 (weight/volume). The density of the solution is 1.84 g/cc.

Answer 1

Given, 93% H2SO4 solution (weight/volume).

It means 93 g of H2SO4 present in 100 mL of solution,

therefore, weight of H2SO4 = 93 g

Volume of solution = 100 mL

  .'. Weight of solution = 100 x 1.84 = 184 g

Thus wait of water = 184 - 93 = 91 g

Molarity = 0.948/ 91 ×1000 = 10.42

Answer 2

Answer:

Explanation:

Given, 93% H2SO4 solution (weight/volume).

It means 93 g of H2SO4 present in 100 mL of solution,

therefore, weight of H2SO4 = 93 g

Volume of solution = 100 mL

 .'. Weight of solution = 100 x 1.84 = 184 g

Thus wait of water = 184 - 93 = 91 g

Molarity = 0.948/ 91 ×1000 = 10.42