Physics, asked by rithish5564, 11 months ago

How to find intensity by young's double slit experiment?

Answers

Answered by Anonymous
0

The answer is wrong.

The steps are:

I = Io cos^2 (ø/2)

1. ø = 2pi/lambda * lambda/4 = pi/2

I = Io cos^2 ((pi/2)/2) = Io cos^2 (pi/4) = Io (1/sqrt(2))^2 = Io/2

2. ø = 2pi/lambda * lambda/3 = 2pi/3

I = Io cos^2 ((2pi/3)/2) = Io cos^2 (pi/3) = Io (1/2)^2 = Io/4

Answered by Anonymous
0

Answer:

The intensity at the maximum in the Young's double slit experiment is I0. Distance between two slits is d=5λ, where λ is the wavelength of light used in the experiment.

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