Calculate the Molarity and strength of a solution containing 5g of NaOH in 450ml solution.
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The molar mass of NaOH is 23g+16g+1g=40g.
5g of NaOH =5g/40g.mol^-1 =0.125 mol.
Molarity =(0.125 mol/450 mL)*(1000 mL/1 L) =5/18 mol/L = 0.28 M.
(Actually what has been calculated should be called formality and not molarity because there is no molecule of NaOH in solution.
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